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Grade 10 Exercise 31.6
$\begin{align}(i)30+90+x=&180\\[5pt]
120+x=&180\\[5pt]
x=&180-120\\[5pt]
&\underline{\underline{60^0}}\\
\end{align}$
$\begin{align}(ii)x+x+90=&180\\[5pt]
2x+90=&180\\[5pt]
2x=&90\\[5pt]
&\underline{\underline{45^0}}\\
\end{align}$
$\begin{align}(iii)y+60+90=&180\\[5pt]
y+150=&180\\[5pt]
y=&180-150\\[5pt]
&\underline{\underline{30^0}}\\
90+x+y=&180\\[5pt]
90+x+30=&180\\[5pt]
x=&180-120\\[5pt]
&\underline{\underline{x=60^0}}\\


\end{align}$
Grade 10 Exercise 31.6
$\begin{align}(iv)x+50+90=&180\\[5pt]
x+140=&180\\[5pt]
x=&180-140\\[5pt]
&\underline{\underline{40^0}}\\
\end{align}$
$\begin{align}(v)x+90+90+110=&360\\[5pt]
x+290=&360\\[5pt]
x=&360-290\\[5pt]
&\underline{\underline{70^0}}\\
\end{align}$

By studying this lesson you will be able to

Identify and apply the theorems related to angles in a circle.

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