$\begin{align} &rate=\frac {volume}{time}\\[5pt] &=\frac{0.35\times 1000l}{70}\\[5pt] &=\frac {0.5\times 0.7m^3}{70 seconds}\\[5pt] &=\frac{350}{70}\\[5pt] &=\underline{ \underline {5ls^{-1}}} \end{align}$
$\begin{align} &\text {x y distance}=100\times 1h = 100 km=100t\\[5pt] &\text {y x distance}=60\times t=60t\\[5pt] 100t+60t&=320\\[5pt] 160t&=320\\[5pt] t&=\frac {320}{160}\\[5pt] t&=2h\\[5pt] &=\underline{ \underline {\text {10.00p.m.}}} \end{align}$
$\begin{align} &\text {travelling time}=12-2 = 10h\\[5pt] &\text {speed}=\frac{600km}{10h}=60kmh^{-1}\\[5pt] &\text {distance travelled for 3h}=60\times 3\\[5pt] &=180km\\[5pt] &=\underline{ \underline {\text {60 km}}} \end{align}$

By studying this lesson you will be able to

Solve problems related to distance, time and speed.