$\begin{align}(i)&\text{Intercept = l and (3,10)}\\[5pt] y&=mx+1\\[5pt] 10&=3m+1\\[5pt] 3m&=9\\[5pt] m&=3\\[5pt] &\underline{\underline{y=3x+1}} \end{align}$	$\begin{align}(ii)&\text{Intercept = 2 and (3,3)}\\[5pt] y&=mx+2\\[5pt] 3&=3m+2\\[5pt] 3m&=1\\[5pt] m&=\frac{1}{3}\\[5pt] &\underline{\underline{y=\frac{1}{3}x+2}} \end{align}$	$\begin{align}(iii)&\text{Intercept = 5 and (2,1)}\\[5pt] y&=mx+5\\[5pt] 1&=2m+5\\[5pt] 2m&=-4\\[5pt] m&=-2\\[5pt] &\underline{\underline{y=-2x+5}} \end{align}$
$\begin{align}(iv)&\text{Intercept = 0 and (3,12)}\\[5pt] y&=mx\\[5pt] 12&=3m\\[5pt] m&=4\\[5pt] &\underline{\underline{y=4x}} \end{align}$	$\begin{align}(v)&\text{Intercept = -4 and (3,8)}\\[5pt] y&=mx-4\\[5pt] 8&=3m-4\\[5pt] 3m&=12\\[5pt] m&=4\\[5pt] &\underline{\underline{y=4x-4}} \end{align}$	$\begin{align}(vi)&\text{Intercept = -5 and (-2,-9)}\\[5pt] y&=mx-5\\[5pt] -9&=-2m-5\\[5pt] -2m&=-4\\[5pt] m&=2\\[5pt] &\underline{\underline{y=2x-5}} \end{align}$

By studying this lesson you will be able to

Find the gradient of the graph of a straight line.