$\begin{align}(i)&7.32\\[5pt] &7.32=10^{0.8645}\\[5pt] &\underline{\underline{\text{lg}7.32 = 0.8645}} \end{align}$	$\begin{align}(ii)&1.05\\[5pt] &1.05=10^{0.212}\\[5pt] &\underline{\underline{\text{lg}1.05 = 0.212}} \end{align}$	$\begin{align}(iii)&9.99\\[5pt] &9.99=10^{0.9996}\\[5pt] &\underline{\underline{\text{lg}9.99 = 0.9996}} \end{align}$
$\begin{align}(iv)&5.8\\[5pt] &5.8=10^{0.7634}\\[5pt] &\underline{\underline{\text{lg}5.8 = 0.7634}} \end{align}$	$\begin{align}(v)&9.2\\[5pt] &9.2=10^{0.9638}\\[5pt] &\underline{\underline{\text{lg}9.2 = 0.9638}} \end{align}$	$\begin{align}(vi)&3.1\\[5pt] &3.1=10^{0.4914}\\[5pt] &\underline{\underline{\text{lg}3.1 = 0.4914}} \end{align}$
$\begin{align}(vii)&4\\[5pt] &4=10^{0.6021}\\[5pt] &\underline{\underline{\text{lg}4 = 0.6021}} \end{align}$	$\begin{align}(viii)&7\\[5pt] &7=10^{0.8451}\\[5pt] &\underline{\underline{\text{lg}7 = 0.8451}} \end{align}$	$\begin{align}(ix)&1\\[5pt] &1=10^{0}\\[5pt] &\underline{\underline{\text{lg}1 = 0}} \end{align}$
$\begin{align}(x)&1.01\\[5pt] &1.01=10^{0.0043}\\[5pt] &\underline{\underline{\text{lg}1.01 = 0.0043}} \end{align}$

By studying this lesson you will be able to

Simplify expressions involving the product and quotient of numbers greater than 1, using the logarithms table.