i.	\begin{align*} &\sqrt{5}\\[5pt] &2^2=4 \\[5pt] &3^2=9 \\[5pt] &2.2^2=4.84\\[5pt] &2.3^2=5.29\\[5pt] &\approx\underline{\underline{{2.2}}} \end{align*}	ii.	\begin{align*} &\sqrt{20}\\[5pt] &4^2=16 \\[5pt] &5^2=25 \\[5pt] &4.5^2=20.25\\[5pt] &4.6^2=21.16\\[5pt] &\approx\underline{\underline{{4.5}}} \end{align*}	iii.	\begin{align*} &\sqrt{67}\\[5pt] &8^2=64 \\[5pt] &9^2=81 \\[5pt] &8.2^2=67.24\\[5pt] &8.3^2=68.89\\[5pt] &\approx\underline{\underline{{8.2}}} \end{align*}
iv.	\begin{align*} &\sqrt{115}\\[5pt] &10^2=100 \\[5pt] &11^2=121 \\[5pt] &10.7^2=114.49\\[5pt] &10.8^2=116.64\\[5pt] &\approx\underline{\underline{{10.7}}} \end{align*}	v.	\begin{align*} &\sqrt{1070}\\[5pt] &32^2=1024 \\[5pt] &33^2=1089 \\[5pt] &32.7^2=1069.29\\[5pt] &32.8^2=1075.84\\[5pt] &\approx\underline{\underline{{32.7}}} \end{align*}

By studying this lesson you will be able to

Use the division method to find an approximate value for the square root of a positive number which is not a prefect square.